Different Types of Relations

Void Relation

An empty relation (or void relation) is one in which there is no relation between any elements of a set. For example, if set A = {1, 2, 3} then, one of the void relations can be R = {x, y} where, |x – y| = 8. For empty relation,

R = φ A × A

Universal Relation

A universal (or full relation) is a type of relation in which every element of a set is related to each other. Consider set A = {a, b, c}. Now one of the universal relations will be R = {x, y} where, |x – y| ≥ 0. For universal relation,

R = A × A

Identity Relation

In an identity relation, every element of a set is related to itself only. For example, in a set A = {a, b, c}, the identity relation will be I = {a, a}, {b, b}, {c, c}. For identity relation,

I = {(a, a), a A}

Inverse Relation

Inverse relation is seen when a set has elements which are inverse pairs of another set. For example if set A = {(a, b), (c, d)}, then inverse relation will be R-1 = {(b, a), (d, c)}. So, for an inverse relation,

R-1 = {(b, a): (a, b) R}

Reflexive Relation

In a reflexive relation, every element maps to itself. For example, consider a set A = {1, 2,}. Now an example of reflexive relation will be R = {(1, 1), (2, 2), (1, 2), (2, 1)}. The reflexive relation is given by-

(a, a) R

Symmetric Relation

In a symmetric relation, if a=b is true then b=a is also true. In other words, a relation R is symmetric only if (b, a) R is true when (a,b) R. An example of symmetric relation will be R = {(1, 2), (2, 1)} for a set A = {1, 2}. So, for a symmetric relation,

aRb bRa, a, b A

Transitive Relation

For transitive relation, if (x, y) R, (y, z) R, then (x, z) R. For a transitive relation,

aRb and bRc aRc a, b, c A

Equivalence Relation

If a relation is reflexive, symmetric and transitive at the same time it is known as an equivalence relation.

Sample Problem 1

The relation R defined in A = {1, 2,3} by aRb, if |$a^2 + b^2$| $\leq$ 5. Which of the following is false?
(a) R = {(1, 1), (1, 2), (2, 1), (2, 2), (2, 3), (3, 2), (3,3)} 
(b) $R^{-1}=R$
(c) Domain of R = {1, 2, 3}
(d) Range of R = {5}

Answer:

R = {(1, 1), (1, 2), (2, 1), (2, 2), (2, 3), (3, 2), (3,3)} 

$R^{-1}$ = {(y,x):(x,y) $\in$ R}

$R^{-1}$ = {(1, 1), (1, 2), (2, 1), (2, 2), (2, 3), (3, 2), (3,3)} = R

Domain of R = {x: (x, y) $\in$ R} = {1, 2, 3} and range of R = {y: (x, y) $\in$ R} = {1, 2, 3}

Sample Problem 2

Let R be the relation from A = {2, 3, 4, 5} to B = {3 ,6 , 7, 10} defined by ‘x divides y’, then $R^{-1}$ is equal to
(a) {(6, 2), (3, 3)}
(b) {(6, 2), (10, 2), (3, 3), (6, 3),(10, 5)}
(c) {(6, 2), (10, 2),(3, 3), (6, 3)}
(d) None of the above

Answer: (b)
Given:

A = {2, 3, 4, 5} to B = {3 ,6 , 7, 10}

So, R = {(2, 6), (2, 10), (3, 3), (3, 6),(5, 10)}

⇒ $R^{-1}$ = {(6, 2), (10, 2), (3, 3), (6, 3),(10, 5)}

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