Now, we introduce some operations on sets to construct new sets from the given ones
(i) Union of Two Sets
Let A and B be two sets, then union of A B and is a set of all those elements which are in A or in Bor in both A and B . It is denoted by A $\cup$ B and read as ‘A union B’.
Symbolically, A $\cup$ B = {x: x $\in$ A or x:x $\in$ B}
Clearly, A $\in$ A $\cup$ B
x $\in$ A or x $\in$ B
A $\notin$ A $\cup$ B
x $\notin$ A or x $\notin$ B
The venn diagram of A $\cup$ B is as shown in the figure and the shaded portion represents A $\cup$ B.
(ii) Intersection of Two Sets
If A B and are two sets, then intersection of A B and is a set of all those elements which are in both A B and . The intersection of A B and is denoted by A $\cap$ B and read as “A intersection B”.
Symbolically, A $\cap$ B = {x: x $\in$ A or x:x $\in$ B}
If, A $\in$ A $\cap$ B ⇒ x $\in$ A or x $\in$ B
and if, A $\notin$ A $\cap$ B ⇒ x $\notin$ A or x $\notin$ B
The Venn diagram of A $\cap$ B is as shown in the figure and the shaded region represents A $\cap$ B.
Symbolically, $\bigcap_{i = 1}^{n}A_i$ = {x: x $\in$ $A_i$ for all i}
(iii) Disjoint of Two Sets
Two sets A B and are known as disjoint sets, if A $\cap$ B = $\phi$ i.e., if A and B have no common element. The Venn diagram of disjoint sets as shown in the figure.
e.g., If A = {1, 2, 3} and B = {4, 5, 6}, then A $\cap$ B = { } = $\phi$
So, A and B are disjoint sets.
(iv) Difference of Two Sets
If A and B are two non-empty sets, then difference of A and B is a set of all those elements which are in A but not in B. It is denoted as A - B. If difference of two sets is B - A, then it is a set of those elements which are in B but not in A.
Hence, A - B = {x : x $\in$ A and x $\notin$ B}
and B - A = {x : x $\in$ B and x $\notin$ A}
if x $\in$ A - B ⇒ x $\in$ A but x $\notin B$
and if x $\in$ B - A ⇒ x $\in$ B but x $\notin A$
The Venn diagram of A - B and B - A are as shown in the figure and shaded region represents A - B and B - A.
e.g., If A = {1, 2, 3, 4} and B = {4, 5, 6, 7, 8}
So, A - B = {1, 2, 3} and B - A = {5, 6, 7, 8}
Note
- A - B $\neq$ B - A
- A - B $\subseteq$ A and B - A $\subseteq$ B
- A - $\phi$ = A - A = $\phi$
- The sets A - B and B - A are disjoint sets.
- Symmetric difference can also be written as A $\Delta$ B = (A $\cup$ B) - (A $\cap$ B)
- A $\Delta$ B = B $\Delta$ A = (commutative)
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