An object of mass m travelling with speed v has a head-on collision with another object of mass m travelling with speed v in the opposite direction.

Q#25

An object of mass travelling with speed has a head-on collision with another object of mass travelling with speed in the opposite direction. The two objects stick together after the collision.

What is the total loss of kinetic energy in the collision?

                  ½ mv2                         mv2                                                 2mv2

 

Solution:

Answer: C.

Momentum is a vector quantity and we need to consider the direction.

Since the objects are moving in opposite direction, one of them will have a negative value.

Sum of momentum before collision = mv – mv = 0

 

Kinetic energy is a scalar quantity and so, the direction of motion does not matter.

Sum of KE before collision = ½ mv2 + ½ mv2 = mv2

 

Momentum is always conserved.

Sum of momentum after collision = Sum of momentum before collision = 0

Sum of momentum after collision = 0

2mvf = 0

Giving the speed after collision, vf = 0

That is, the objects do not move after the collision.

KE after collision = 0

Loss in KE = mv2 – 0 = mv2

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