Q# 182: [Current of Electricity > Resistance] (Past Exam Paper – June 2012 Paper 12 Q38)
Four identical resistors are connected in three networks below.
Which arrangement has highest total resistance and which has lowest?
Solution 182:
Answer: C.
Hint: Try to simplify each part of the circuit.
Let the resistance of a resistor = R
For diagram 1:
1/R1 = (1/R + 1/(2R) + 1/R) = 5/2R
So, total resistance R1 = 2R/5
For diagram 2:
Resistance of upper part = R + (1/R + 1/R)-1 = R + R/2 = 3R/2
1/R2 = 2/3R + 1/R = 5/3R.
So, total resistance R2 = 3R/5
For diagram 3:
1/R3 = 1/3R + 1/R = 4/3R
So, total resistance R3 = 3R/4
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