Q#29 (Past Exam Paper – November 2016 Paper 12 Q37)
In the circuit shown, there is a current of 3.0 A in the 2.0 Ω resistor.
What are the values of the current I delivered by the power supply and the voltage V across it?
Solution:
Answer: C.
For the parallel section, the p.d. across each resistor is the same.
p.d. across 2.0 Ω resistor = IR = 3.0 × 2.0 = 6.0 V
The p.d. across the 6.0 Ω resistor is also 6.0 V.
Current through 6.0 Ω resistor = V / R = 6.0 / 6.0 = 1.0 A
Current I = 3.0 + 1.0 = 4.0 A
This same current flows through the 1.5 Ω resistor.
p.d. across 1.5 Ω resistor = IR = 4.0 × 1.5 = 6.0 V
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