Q#18 (Past Exam Paper – November 2015 Paper 12 Q20)
The diagram shows the cross-section of an Olympic-size swimming pool filled with water. It is not drawn to scale. The density of the water is 1000 kg m-3.
What is the difference in pressure between X and Y?
A 0.35 kPa
B 3.4 kPa
C 21.3 kPa
D 58.9 kPa
B 3.4 kPa
C 21.3 kPa
D 58.9 kPa
Solution:
Answer: B.
Pressure is due to the liquid above the point.
Pressure in liquid = hρg
where h is the depth under water
Pressure at X = hρg = 2.35 × ρg
Pressure at Y = hρg = 2.00 × ρg
Difference in pressure = pressure at X – pressure at Y
Difference in pressure = 2.35 × ρg – 2.00 × ρg = (2.35 – 2.00) × 1000 × 9.81
Difference in pressure = 3433.5 Pa = 3.4 kPa
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